Linux – Rekursives Ersetzen von Leerzeichen durch Unterstrich

Um in einem Pfad alle Ordner- und Datei-Namen rekursiv umzubenennen, braucht es folgendes Script:

#!/bin/bash

[ "`whoami`" = root ] || exec sudo "$0" "$@"

echo -en "\n BEWARE! Starting from current directory (`pwd`),"
echo -en " files and directories with spaces in name  will be renamed automatically.\n"
echo -en "\n Press \"ENTER\" to continue or \"N\" to exit:"
read ops
case "$ops" in
        n|N)
            echo -en "\n Canceled by User. Exiting...\n"
            exit 1 ;;
        *)
            echo -en "\n Starting...\n" ;;
esac

number=0                    # Number of renamed.
number_not=0		    # Number of not renamed.
IFS=$'\n'
array=( `find ./ -type d` ) # Find catalogs recursively.

for (( i = ${#array[@]}; i; )); do
     pushd "${array[--i]}" >/dev/null 2>&1
     for name in *
     do
	     echo "$name" | grep -q " "
	     if [ $? -eq 0 ]
	     then
	        newname=`echo $name | sed -e "s/ /_/g"`
		if [ -e $newname ]
        	then
			let "number_not +=1"
                	echo " Not renaming: $name"
        	else
                	let "number += 1"
                	echo "$number Renaming: $name"
		        mv "$name" "$newname"
		fi
	     fi
     done
     popd >/dev/null 2>&1
done

echo -en "\n All operations are ready."

if [ "$number_not" -ne "0" ]
  then echo -en "\n $number_not not renamed."
fi

if [ "$number" -eq "0" ]
  then echo -en "\n Nothing been renamed.\n"
elif [ "$number" -eq "1" ]
   then echo -en "\n $number renamed.\n"
   else echo -en "\n Renamed files and catalogs: $number\n"
fi

exit 0

Vorsicht! Es werden ALLE Ordner und Dateien umbenannt ab dem Pfad, in dem Ihr Euch befindet.

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